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2x^2=30-5x
We move all terms to the left:
2x^2-(30-5x)=0
We add all the numbers together, and all the variables
2x^2-(-5x+30)=0
We get rid of parentheses
2x^2+5x-30=0
a = 2; b = 5; c = -30;
Δ = b2-4ac
Δ = 52-4·2·(-30)
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{265}}{2*2}=\frac{-5-\sqrt{265}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{265}}{2*2}=\frac{-5+\sqrt{265}}{4} $
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